Home Chemistry Chemical Kinetics Rate of a Reaction Hydrogenation of vegetable ghee at 25ºC redu…
Chemistry Chemical Kinetics Rate of a Reaction Single Correct MCQ
Published on: August 14, 2026

Hydrogenation of vegetable ghee at 25ºC reduces the pressure of H 2 from 2 atm to 1.2 atm in 50 minute. Calculate the rate of reaction in terms of change :

A
In pressure per minute.
B
In molarity per second.

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Text Solution

Verified by Experts
The correct answer is:
A

1.6 × 10 –2 atm min –1

1.09 × 10 –5 mol liter –1 sec –1

Sol. Rate of reaction = = = = 1.6 × 10 –2 atm min –1

 Change in molarity may be derived by PV = nRT ;

Δ C = = = 0.0327

Rate of reaction = = = 1.09 × 10 –5 mol liter –1 sec –1

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